977. Squares of a Sorted Array

Given an integer array nums sorted in non-decreasing order, return an array of the squares of each number sorted in non-decreasing order.

采取双指针,同时比较两侧的正负及大小。

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class Solution {
public int[] sortedSquares(int[] nums) {
int left = 0;
int right = nums.length - 1;
int i = nums.length-1;
int[] ans = new int[nums.length];

while (left <= right) {
if ( nums[left] < 0 ){
if ( (-nums[left]) < nums[right] ){
ans[i] = nums[right] * nums[right];
right--;
}
else {
ans[i] = nums[left] * nums[left];
left++;
}
i--;
}
else{
if ( nums[left] < nums[right] ){
ans[i] = nums[right] * nums[right];
right--;
}
else{
ans[i] = nums[left] * nums[left];
left++;
}
i--;
}
}
return ans;
}
}

Author

Xander

Posted on

2022-04-03

Updated on

2022-04-20

Licensed under

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